|
def | chunked (iterable, n, strict=False) |
|
def | first (iterable, default=_marker) |
|
def | last (iterable, default=_marker) |
|
def | nth_or_last (iterable, n, default=_marker) |
|
def | collate (*iterables, **kwargs) |
|
def | consumer (func) |
|
def | ilen (iterable) |
|
def | iterate (func, start) |
|
def | with_iter (context_manager) |
|
def | one (iterable, too_short=None, too_long=None) |
|
def | distinct_permutations (iterable, r=None) |
|
def | intersperse (e, iterable, n=1) |
|
def | unique_to_each (*iterables) |
|
def | windowed (seq, n, fillvalue=None, step=1) |
|
def | substrings (iterable) |
|
def | substrings_indexes (seq, reverse=False) |
|
def | spy (iterable, n=1) |
|
def | interleave (*iterables) |
|
def | interleave_longest (*iterables) |
|
def | collapse (iterable, base_type=None, levels=None) |
|
def | side_effect (func, iterable, chunk_size=None, before=None, after=None) |
|
def | sliced (seq, n, strict=False) |
|
def | split_at (iterable, pred, maxsplit=-1, keep_separator=False) |
|
def | split_before (iterable, pred, maxsplit=-1) |
|
def | split_after (iterable, pred, maxsplit=-1) |
|
def | split_when (iterable, pred, maxsplit=-1) |
|
def | split_into (iterable, sizes) |
|
def | padded (iterable, fillvalue=None, n=None, next_multiple=False) |
|
def | repeat_last (iterable, default=None) |
|
def | distribute (n, iterable) |
|
def | stagger (iterable, offsets=(-1, 0, 1), longest=False, fillvalue=None) |
|
def | zip_equal (*iterables) |
|
def | zip_offset (*iterables, offsets, longest=False, fillvalue=None) |
|
def | sort_together (iterables, key_list=(0,), key=None, reverse=False) |
|
def | unzip (iterable) |
|
def | divide (n, iterable) |
|
def | always_iterable (obj, base_type=(str, bytes)) |
|
def | adjacent (predicate, iterable, distance=1) |
|
def | groupby_transform (iterable, keyfunc=None, valuefunc=None, reducefunc=None) |
|
def | count_cycle (iterable, n=None) |
|
def | mark_ends (iterable) |
|
def | locate (iterable, pred=bool, window_size=None) |
|
def | lstrip (iterable, pred) |
|
def | rstrip (iterable, pred) |
|
def | strip (iterable, pred) |
|
def | always_reversible (iterable) |
|
def | consecutive_groups (iterable, ordering=lambda x:x) |
|
def | difference (iterable, func=sub, *initial=None) |
|
def | exactly_n (iterable, n, predicate=bool) |
|
def | circular_shifts (iterable) |
|
def | make_decorator (wrapping_func, result_index=0) |
|
def | map_reduce (iterable, keyfunc, valuefunc=None, reducefunc=None) |
|
def | rlocate (iterable, pred=bool, window_size=None) |
|
def | replace (iterable, pred, substitutes, count=None, window_size=1) |
|
def | partitions (iterable) |
|
def | set_partitions (iterable, k=None) |
|
def | only (iterable, default=None, too_long=None) |
|
def | ichunked (iterable, n) |
|
def | distinct_combinations (iterable, r) |
|
def | filter_except (validator, iterable, *exceptions) |
|
def | map_except (function, iterable, *exceptions) |
|
def | sample (iterable, k, weights=None) |
|
def | is_sorted (iterable, key=None, reverse=False) |
|
def | windowed_complete (iterable, n) |
|
def | all_unique (iterable, key=None) |
|
def | nth_product (index, *args) |
|
def | nth_permutation (iterable, r, index) |
|
def | value_chain (*args) |
|
def | product_index (element, *args) |
|
def | combination_index (element, iterable) |
|
def | permutation_index (element, iterable) |
|
def setuptools._vendor.more_itertools.more.adjacent |
( |
|
predicate, |
|
|
|
iterable, |
|
|
|
distance = 1 |
|
) |
| |
Return an iterable over `(bool, item)` tuples where the `item` is
drawn from *iterable* and the `bool` indicates whether
that item satisfies the *predicate* or is adjacent to an item that does.
For example, to find whether items are adjacent to a ``3``::
>>> list(adjacent(lambda x: x == 3, range(6)))
[(False, 0), (False, 1), (True, 2), (True, 3), (True, 4), (False, 5)]
Set *distance* to change what counts as adjacent. For example, to find
whether items are two places away from a ``3``:
>>> list(adjacent(lambda x: x == 3, range(6), distance=2))
[(False, 0), (True, 1), (True, 2), (True, 3), (True, 4), (True, 5)]
This is useful for contextualizing the results of a search function.
For example, a code comparison tool might want to identify lines that
have changed, but also surrounding lines to give the viewer of the diff
context.
The predicate function will only be called once for each item in the
iterable.
See also :func:`groupby_transform`, which can be used with this function
to group ranges of items with the same `bool` value.
def setuptools._vendor.more_itertools.more.chunked |
( |
|
iterable, |
|
|
|
n, |
|
|
|
strict = False |
|
) |
| |
Break *iterable* into lists of length *n*:
>>> list(chunked([1, 2, 3, 4, 5, 6], 3))
[[1, 2, 3], [4, 5, 6]]
By the default, the last yielded list will have fewer than *n* elements
if the length of *iterable* is not divisible by *n*:
>>> list(chunked([1, 2, 3, 4, 5, 6, 7, 8], 3))
[[1, 2, 3], [4, 5, 6], [7, 8]]
To use a fill-in value instead, see the :func:`grouper` recipe.
If the length of *iterable* is not divisible by *n* and *strict* is
``True``, then ``ValueError`` will be raised before the last
list is yielded.
def setuptools._vendor.more_itertools.more.collapse |
( |
|
iterable, |
|
|
|
base_type = None , |
|
|
|
levels = None |
|
) |
| |
Flatten an iterable with multiple levels of nesting (e.g., a list of
lists of tuples) into non-iterable types.
>>> iterable = [(1, 2), ([3, 4], [[5], [6]])]
>>> list(collapse(iterable))
[1, 2, 3, 4, 5, 6]
Binary and text strings are not considered iterable and
will not be collapsed.
To avoid collapsing other types, specify *base_type*:
>>> iterable = ['ab', ('cd', 'ef'), ['gh', 'ij']]
>>> list(collapse(iterable, base_type=tuple))
['ab', ('cd', 'ef'), 'gh', 'ij']
Specify *levels* to stop flattening after a certain level:
>>> iterable = [('a', ['b']), ('c', ['d'])]
>>> list(collapse(iterable)) # Fully flattened
['a', 'b', 'c', 'd']
>>> list(collapse(iterable, levels=1)) # Only one level flattened
['a', ['b'], 'c', ['d']]
def setuptools._vendor.more_itertools.more.collate |
( |
* |
iterables, |
|
|
** |
kwargs |
|
) |
| |
Return a sorted merge of the items from each of several already-sorted
*iterables*.
>>> list(collate('ACDZ', 'AZ', 'JKL'))
['A', 'A', 'C', 'D', 'J', 'K', 'L', 'Z', 'Z']
Works lazily, keeping only the next value from each iterable in memory. Use
:func:`collate` to, for example, perform a n-way mergesort of items that
don't fit in memory.
If a *key* function is specified, the iterables will be sorted according
to its result:
>>> key = lambda s: int(s) # Sort by numeric value, not by string
>>> list(collate(['1', '10'], ['2', '11'], key=key))
['1', '2', '10', '11']
If the *iterables* are sorted in descending order, set *reverse* to
``True``:
>>> list(collate([5, 3, 1], [4, 2, 0], reverse=True))
[5, 4, 3, 2, 1, 0]
If the elements of the passed-in iterables are out of order, you might get
unexpected results.
On Python 3.5+, this function is an alias for :func:`heapq.merge`.
def setuptools._vendor.more_itertools.more.consecutive_groups |
( |
|
iterable, |
|
|
|
ordering = lambda x: x |
|
) |
| |
Yield groups of consecutive items using :func:`itertools.groupby`.
The *ordering* function determines whether two items are adjacent by
returning their position.
By default, the ordering function is the identity function. This is
suitable for finding runs of numbers:
>>> iterable = [1, 10, 11, 12, 20, 30, 31, 32, 33, 40]
>>> for group in consecutive_groups(iterable):
... print(list(group))
[1]
[10, 11, 12]
[20]
[30, 31, 32, 33]
[40]
For finding runs of adjacent letters, try using the :meth:`index` method
of a string of letters:
>>> from string import ascii_lowercase
>>> iterable = 'abcdfgilmnop'
>>> ordering = ascii_lowercase.index
>>> for group in consecutive_groups(iterable, ordering):
... print(list(group))
['a', 'b', 'c', 'd']
['f', 'g']
['i']
['l', 'm', 'n', 'o', 'p']
Each group of consecutive items is an iterator that shares it source with
*iterable*. When an an output group is advanced, the previous group is
no longer available unless its elements are copied (e.g., into a ``list``).
>>> iterable = [1, 2, 11, 12, 21, 22]
>>> saved_groups = []
>>> for group in consecutive_groups(iterable):
... saved_groups.append(list(group)) # Copy group elements
>>> saved_groups
[[1, 2], [11, 12], [21, 22]]
def setuptools._vendor.more_itertools.more.difference |
( |
|
iterable, |
|
|
|
func = sub , |
|
|
* |
initial = None |
|
) |
| |
This function is the inverse of :func:`itertools.accumulate`. By default
it will compute the first difference of *iterable* using
:func:`operator.sub`:
>>> from itertools import accumulate
>>> iterable = accumulate([0, 1, 2, 3, 4]) # produces 0, 1, 3, 6, 10
>>> list(difference(iterable))
[0, 1, 2, 3, 4]
*func* defaults to :func:`operator.sub`, but other functions can be
specified. They will be applied as follows::
A, B, C, D, ... --> A, func(B, A), func(C, B), func(D, C), ...
For example, to do progressive division:
>>> iterable = [1, 2, 6, 24, 120]
>>> func = lambda x, y: x // y
>>> list(difference(iterable, func))
[1, 2, 3, 4, 5]
If the *initial* keyword is set, the first element will be skipped when
computing successive differences.
>>> it = [10, 11, 13, 16] # from accumulate([1, 2, 3], initial=10)
>>> list(difference(it, initial=10))
[1, 2, 3]
def setuptools._vendor.more_itertools.more.distinct_permutations |
( |
|
iterable, |
|
|
|
r = None |
|
) |
| |
Yield successive distinct permutations of the elements in *iterable*.
>>> sorted(distinct_permutations([1, 0, 1]))
[(0, 1, 1), (1, 0, 1), (1, 1, 0)]
Equivalent to ``set(permutations(iterable))``, except duplicates are not
generated and thrown away. For larger input sequences this is much more
efficient.
Duplicate permutations arise when there are duplicated elements in the
input iterable. The number of items returned is
`n! / (x_1! * x_2! * ... * x_n!)`, where `n` is the total number of
items input, and each `x_i` is the count of a distinct item in the input
sequence.
If *r* is given, only the *r*-length permutations are yielded.
>>> sorted(distinct_permutations([1, 0, 1], r=2))
[(0, 1), (1, 0), (1, 1)]
>>> sorted(distinct_permutations(range(3), r=2))
[(0, 1), (0, 2), (1, 0), (1, 2), (2, 0), (2, 1)]
def setuptools._vendor.more_itertools.more.distribute |
( |
|
n, |
|
|
|
iterable |
|
) |
| |
Distribute the items from *iterable* among *n* smaller iterables.
>>> group_1, group_2 = distribute(2, [1, 2, 3, 4, 5, 6])
>>> list(group_1)
[1, 3, 5]
>>> list(group_2)
[2, 4, 6]
If the length of *iterable* is not evenly divisible by *n*, then the
length of the returned iterables will not be identical:
>>> children = distribute(3, [1, 2, 3, 4, 5, 6, 7])
>>> [list(c) for c in children]
[[1, 4, 7], [2, 5], [3, 6]]
If the length of *iterable* is smaller than *n*, then the last returned
iterables will be empty:
>>> children = distribute(5, [1, 2, 3])
>>> [list(c) for c in children]
[[1], [2], [3], [], []]
This function uses :func:`itertools.tee` and may require significant
storage. If you need the order items in the smaller iterables to match the
original iterable, see :func:`divide`.
def setuptools._vendor.more_itertools.more.divide |
( |
|
n, |
|
|
|
iterable |
|
) |
| |
Divide the elements from *iterable* into *n* parts, maintaining
order.
>>> group_1, group_2 = divide(2, [1, 2, 3, 4, 5, 6])
>>> list(group_1)
[1, 2, 3]
>>> list(group_2)
[4, 5, 6]
If the length of *iterable* is not evenly divisible by *n*, then the
length of the returned iterables will not be identical:
>>> children = divide(3, [1, 2, 3, 4, 5, 6, 7])
>>> [list(c) for c in children]
[[1, 2, 3], [4, 5], [6, 7]]
If the length of the iterable is smaller than n, then the last returned
iterables will be empty:
>>> children = divide(5, [1, 2, 3])
>>> [list(c) for c in children]
[[1], [2], [3], [], []]
This function will exhaust the iterable before returning and may require
significant storage. If order is not important, see :func:`distribute`,
which does not first pull the iterable into memory.
def setuptools._vendor.more_itertools.more.groupby_transform |
( |
|
iterable, |
|
|
|
keyfunc = None , |
|
|
|
valuefunc = None , |
|
|
|
reducefunc = None |
|
) |
| |
An extension of :func:`itertools.groupby` that can apply transformations
to the grouped data.
* *keyfunc* is a function computing a key value for each item in *iterable*
* *valuefunc* is a function that transforms the individual items from
*iterable* after grouping
* *reducefunc* is a function that transforms each group of items
>>> iterable = 'aAAbBBcCC'
>>> keyfunc = lambda k: k.upper()
>>> valuefunc = lambda v: v.lower()
>>> reducefunc = lambda g: ''.join(g)
>>> list(groupby_transform(iterable, keyfunc, valuefunc, reducefunc))
[('A', 'aaa'), ('B', 'bbb'), ('C', 'ccc')]
Each optional argument defaults to an identity function if not specified.
:func:`groupby_transform` is useful when grouping elements of an iterable
using a separate iterable as the key. To do this, :func:`zip` the iterables
and pass a *keyfunc* that extracts the first element and a *valuefunc*
that extracts the second element::
>>> from operator import itemgetter
>>> keys = [0, 0, 1, 1, 1, 2, 2, 2, 3]
>>> values = 'abcdefghi'
>>> iterable = zip(keys, values)
>>> grouper = groupby_transform(iterable, itemgetter(0), itemgetter(1))
>>> [(k, ''.join(g)) for k, g in grouper]
[(0, 'ab'), (1, 'cde'), (2, 'fgh'), (3, 'i')]
Note that the order of items in the iterable is significant.
Only adjacent items are grouped together, so if you don't want any
duplicate groups, you should sort the iterable by the key function.
def setuptools._vendor.more_itertools.more.intersperse |
( |
|
e, |
|
|
|
iterable, |
|
|
|
n = 1 |
|
) |
| |
Intersperse filler element *e* among the items in *iterable*, leaving
*n* items between each filler element.
>>> list(intersperse('!', [1, 2, 3, 4, 5]))
[1, '!', 2, '!', 3, '!', 4, '!', 5]
>>> list(intersperse(None, [1, 2, 3, 4, 5], n=2))
[1, 2, None, 3, 4, None, 5]
def setuptools._vendor.more_itertools.more.locate |
( |
|
iterable, |
|
|
|
pred = bool , |
|
|
|
window_size = None |
|
) |
| |
Yield the index of each item in *iterable* for which *pred* returns
``True``.
*pred* defaults to :func:`bool`, which will select truthy items:
>>> list(locate([0, 1, 1, 0, 1, 0, 0]))
[1, 2, 4]
Set *pred* to a custom function to, e.g., find the indexes for a particular
item.
>>> list(locate(['a', 'b', 'c', 'b'], lambda x: x == 'b'))
[1, 3]
If *window_size* is given, then the *pred* function will be called with
that many items. This enables searching for sub-sequences:
>>> iterable = [0, 1, 2, 3, 0, 1, 2, 3, 0, 1, 2, 3]
>>> pred = lambda *args: args == (1, 2, 3)
>>> list(locate(iterable, pred=pred, window_size=3))
[1, 5, 9]
Use with :func:`seekable` to find indexes and then retrieve the associated
items:
>>> from itertools import count
>>> from more_itertools import seekable
>>> source = (3 * n + 1 if (n % 2) else n // 2 for n in count())
>>> it = seekable(source)
>>> pred = lambda x: x > 100
>>> indexes = locate(it, pred=pred)
>>> i = next(indexes)
>>> it.seek(i)
>>> next(it)
106
def setuptools._vendor.more_itertools.more.make_decorator |
( |
|
wrapping_func, |
|
|
|
result_index = 0 |
|
) |
| |
Return a decorator version of *wrapping_func*, which is a function that
modifies an iterable. *result_index* is the position in that function's
signature where the iterable goes.
This lets you use itertools on the "production end," i.e. at function
definition. This can augment what the function returns without changing the
function's code.
For example, to produce a decorator version of :func:`chunked`:
>>> from more_itertools import chunked
>>> chunker = make_decorator(chunked, result_index=0)
>>> @chunker(3)
... def iter_range(n):
... return iter(range(n))
...
>>> list(iter_range(9))
[[0, 1, 2], [3, 4, 5], [6, 7, 8]]
To only allow truthy items to be returned:
>>> truth_serum = make_decorator(filter, result_index=1)
>>> @truth_serum(bool)
... def boolean_test():
... return [0, 1, '', ' ', False, True]
...
>>> list(boolean_test())
[1, ' ', True]
The :func:`peekable` and :func:`seekable` wrappers make for practical
decorators:
>>> from more_itertools import peekable
>>> peekable_function = make_decorator(peekable)
>>> @peekable_function()
... def str_range(*args):
... return (str(x) for x in range(*args))
...
>>> it = str_range(1, 20, 2)
>>> next(it), next(it), next(it)
('1', '3', '5')
>>> it.peek()
'7'
>>> next(it)
'7'
def setuptools._vendor.more_itertools.more.map_reduce |
( |
|
iterable, |
|
|
|
keyfunc, |
|
|
|
valuefunc = None , |
|
|
|
reducefunc = None |
|
) |
| |
Return a dictionary that maps the items in *iterable* to categories
defined by *keyfunc*, transforms them with *valuefunc*, and
then summarizes them by category with *reducefunc*.
*valuefunc* defaults to the identity function if it is unspecified.
If *reducefunc* is unspecified, no summarization takes place:
>>> keyfunc = lambda x: x.upper()
>>> result = map_reduce('abbccc', keyfunc)
>>> sorted(result.items())
[('A', ['a']), ('B', ['b', 'b']), ('C', ['c', 'c', 'c'])]
Specifying *valuefunc* transforms the categorized items:
>>> keyfunc = lambda x: x.upper()
>>> valuefunc = lambda x: 1
>>> result = map_reduce('abbccc', keyfunc, valuefunc)
>>> sorted(result.items())
[('A', [1]), ('B', [1, 1]), ('C', [1, 1, 1])]
Specifying *reducefunc* summarizes the categorized items:
>>> keyfunc = lambda x: x.upper()
>>> valuefunc = lambda x: 1
>>> reducefunc = sum
>>> result = map_reduce('abbccc', keyfunc, valuefunc, reducefunc)
>>> sorted(result.items())
[('A', 1), ('B', 2), ('C', 3)]
You may want to filter the input iterable before applying the map/reduce
procedure:
>>> all_items = range(30)
>>> items = [x for x in all_items if 10 <= x <= 20] # Filter
>>> keyfunc = lambda x: x % 2 # Evens map to 0; odds to 1
>>> categories = map_reduce(items, keyfunc=keyfunc)
>>> sorted(categories.items())
[(0, [10, 12, 14, 16, 18, 20]), (1, [11, 13, 15, 17, 19])]
>>> summaries = map_reduce(items, keyfunc=keyfunc, reducefunc=sum)
>>> sorted(summaries.items())
[(0, 90), (1, 75)]
Note that all items in the iterable are gathered into a list before the
summarization step, which may require significant storage.
The returned object is a :obj:`collections.defaultdict` with the
``default_factory`` set to ``None``, such that it behaves like a normal
dictionary.
def setuptools._vendor.more_itertools.more.padded |
( |
|
iterable, |
|
|
|
fillvalue = None , |
|
|
|
n = None , |
|
|
|
next_multiple = False |
|
) |
| |
Yield the elements from *iterable*, followed by *fillvalue*, such that
at least *n* items are emitted.
>>> list(padded([1, 2, 3], '?', 5))
[1, 2, 3, '?', '?']
If *next_multiple* is ``True``, *fillvalue* will be emitted until the
number of items emitted is a multiple of *n*::
>>> list(padded([1, 2, 3, 4], n=3, next_multiple=True))
[1, 2, 3, 4, None, None]
If *n* is ``None``, *fillvalue* will be emitted indefinitely.
def setuptools._vendor.more_itertools.more.replace |
( |
|
iterable, |
|
|
|
pred, |
|
|
|
substitutes, |
|
|
|
count = None , |
|
|
|
window_size = 1 |
|
) |
| |
Yield the items from *iterable*, replacing the items for which *pred*
returns ``True`` with the items from the iterable *substitutes*.
>>> iterable = [1, 1, 0, 1, 1, 0, 1, 1]
>>> pred = lambda x: x == 0
>>> substitutes = (2, 3)
>>> list(replace(iterable, pred, substitutes))
[1, 1, 2, 3, 1, 1, 2, 3, 1, 1]
If *count* is given, the number of replacements will be limited:
>>> iterable = [1, 1, 0, 1, 1, 0, 1, 1, 0]
>>> pred = lambda x: x == 0
>>> substitutes = [None]
>>> list(replace(iterable, pred, substitutes, count=2))
[1, 1, None, 1, 1, None, 1, 1, 0]
Use *window_size* to control the number of items passed as arguments to
*pred*. This allows for locating and replacing subsequences.
>>> iterable = [0, 1, 2, 5, 0, 1, 2, 5]
>>> window_size = 3
>>> pred = lambda *args: args == (0, 1, 2) # 3 items passed to pred
>>> substitutes = [3, 4] # Splice in these items
>>> list(replace(iterable, pred, substitutes, window_size=window_size))
[3, 4, 5, 3, 4, 5]
def setuptools._vendor.more_itertools.more.rlocate |
( |
|
iterable, |
|
|
|
pred = bool , |
|
|
|
window_size = None |
|
) |
| |
Yield the index of each item in *iterable* for which *pred* returns
``True``, starting from the right and moving left.
*pred* defaults to :func:`bool`, which will select truthy items:
>>> list(rlocate([0, 1, 1, 0, 1, 0, 0])) # Truthy at 1, 2, and 4
[4, 2, 1]
Set *pred* to a custom function to, e.g., find the indexes for a particular
item:
>>> iterable = iter('abcb')
>>> pred = lambda x: x == 'b'
>>> list(rlocate(iterable, pred))
[3, 1]
If *window_size* is given, then the *pred* function will be called with
that many items. This enables searching for sub-sequences:
>>> iterable = [0, 1, 2, 3, 0, 1, 2, 3, 0, 1, 2, 3]
>>> pred = lambda *args: args == (1, 2, 3)
>>> list(rlocate(iterable, pred=pred, window_size=3))
[9, 5, 1]
Beware, this function won't return anything for infinite iterables.
If *iterable* is reversible, ``rlocate`` will reverse it and search from
the right. Otherwise, it will search from the left and return the results
in reverse order.
See :func:`locate` to for other example applications.
def setuptools._vendor.more_itertools.more.sample |
( |
|
iterable, |
|
|
|
k, |
|
|
|
weights = None |
|
) |
| |
Return a *k*-length list of elements chosen (without replacement)
from the *iterable*. Like :func:`random.sample`, but works on iterables
of unknown length.
>>> iterable = range(100)
>>> sample(iterable, 5) # doctest: +SKIP
[81, 60, 96, 16, 4]
An iterable with *weights* may also be given:
>>> iterable = range(100)
>>> weights = (i * i + 1 for i in range(100))
>>> sampled = sample(iterable, 5, weights=weights) # doctest: +SKIP
[79, 67, 74, 66, 78]
The algorithm can also be used to generate weighted random permutations.
The relative weight of each item determines the probability that it
appears late in the permutation.
>>> data = "abcdefgh"
>>> weights = range(1, len(data) + 1)
>>> sample(data, k=len(data), weights=weights) # doctest: +SKIP
['c', 'a', 'b', 'e', 'g', 'd', 'h', 'f']
def setuptools._vendor.more_itertools.more.side_effect |
( |
|
func, |
|
|
|
iterable, |
|
|
|
chunk_size = None , |
|
|
|
before = None , |
|
|
|
after = None |
|
) |
| |
Invoke *func* on each item in *iterable* (or on each *chunk_size* group
of items) before yielding the item.
`func` must be a function that takes a single argument. Its return value
will be discarded.
*before* and *after* are optional functions that take no arguments. They
will be executed before iteration starts and after it ends, respectively.
`side_effect` can be used for logging, updating progress bars, or anything
that is not functionally "pure."
Emitting a status message:
>>> from more_itertools import consume
>>> func = lambda item: print('Received {}'.format(item))
>>> consume(side_effect(func, range(2)))
Received 0
Received 1
Operating on chunks of items:
>>> pair_sums = []
>>> func = lambda chunk: pair_sums.append(sum(chunk))
>>> list(side_effect(func, [0, 1, 2, 3, 4, 5], 2))
[0, 1, 2, 3, 4, 5]
>>> list(pair_sums)
[1, 5, 9]
Writing to a file-like object:
>>> from io import StringIO
>>> from more_itertools import consume
>>> f = StringIO()
>>> func = lambda x: print(x, file=f)
>>> before = lambda: print(u'HEADER', file=f)
>>> after = f.close
>>> it = [u'a', u'b', u'c']
>>> consume(side_effect(func, it, before=before, after=after))
>>> f.closed
True
def setuptools._vendor.more_itertools.more.sliced |
( |
|
seq, |
|
|
|
n, |
|
|
|
strict = False |
|
) |
| |
Yield slices of length *n* from the sequence *seq*.
>>> list(sliced((1, 2, 3, 4, 5, 6), 3))
[(1, 2, 3), (4, 5, 6)]
By the default, the last yielded slice will have fewer than *n* elements
if the length of *seq* is not divisible by *n*:
>>> list(sliced((1, 2, 3, 4, 5, 6, 7, 8), 3))
[(1, 2, 3), (4, 5, 6), (7, 8)]
If the length of *seq* is not divisible by *n* and *strict* is
``True``, then ``ValueError`` will be raised before the last
slice is yielded.
This function will only work for iterables that support slicing.
For non-sliceable iterables, see :func:`chunked`.
def setuptools._vendor.more_itertools.more.sort_together |
( |
|
iterables, |
|
|
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key_list = (0,) , |
|
|
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key = None , |
|
|
|
reverse = False |
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) |
| |
Return the input iterables sorted together, with *key_list* as the
priority for sorting. All iterables are trimmed to the length of the
shortest one.
This can be used like the sorting function in a spreadsheet. If each
iterable represents a column of data, the key list determines which
columns are used for sorting.
By default, all iterables are sorted using the ``0``-th iterable::
>>> iterables = [(4, 3, 2, 1), ('a', 'b', 'c', 'd')]
>>> sort_together(iterables)
[(1, 2, 3, 4), ('d', 'c', 'b', 'a')]
Set a different key list to sort according to another iterable.
Specifying multiple keys dictates how ties are broken::
>>> iterables = [(3, 1, 2), (0, 1, 0), ('c', 'b', 'a')]
>>> sort_together(iterables, key_list=(1, 2))
[(2, 3, 1), (0, 0, 1), ('a', 'c', 'b')]
To sort by a function of the elements of the iterable, pass a *key*
function. Its arguments are the elements of the iterables corresponding to
the key list::
>>> names = ('a', 'b', 'c')
>>> lengths = (1, 2, 3)
>>> widths = (5, 2, 1)
>>> def area(length, width):
... return length * width
>>> sort_together([names, lengths, widths], key_list=(1, 2), key=area)
[('c', 'b', 'a'), (3, 2, 1), (1, 2, 5)]
Set *reverse* to ``True`` to sort in descending order.
>>> sort_together([(1, 2, 3), ('c', 'b', 'a')], reverse=True)
[(3, 2, 1), ('a', 'b', 'c')]
def setuptools._vendor.more_itertools.more.split_after |
( |
|
iterable, |
|
|
|
pred, |
|
|
|
maxsplit = -1 |
|
) |
| |
Yield lists of items from *iterable*, where each list ends with an
item where callable *pred* returns ``True``:
>>> list(split_after('one1two2', lambda s: s.isdigit()))
[['o', 'n', 'e', '1'], ['t', 'w', 'o', '2']]
>>> list(split_after(range(10), lambda n: n % 3 == 0))
[[0], [1, 2, 3], [4, 5, 6], [7, 8, 9]]
At most *maxsplit* splits are done. If *maxsplit* is not specified or -1,
then there is no limit on the number of splits:
>>> list(split_after(range(10), lambda n: n % 3 == 0, maxsplit=2))
[[0], [1, 2, 3], [4, 5, 6, 7, 8, 9]]
def setuptools._vendor.more_itertools.more.split_at |
( |
|
iterable, |
|
|
|
pred, |
|
|
|
maxsplit = -1 , |
|
|
|
keep_separator = False |
|
) |
| |
Yield lists of items from *iterable*, where each list is delimited by
an item where callable *pred* returns ``True``.
>>> list(split_at('abcdcba', lambda x: x == 'b'))
[['a'], ['c', 'd', 'c'], ['a']]
>>> list(split_at(range(10), lambda n: n % 2 == 1))
[[0], [2], [4], [6], [8], []]
At most *maxsplit* splits are done. If *maxsplit* is not specified or -1,
then there is no limit on the number of splits:
>>> list(split_at(range(10), lambda n: n % 2 == 1, maxsplit=2))
[[0], [2], [4, 5, 6, 7, 8, 9]]
By default, the delimiting items are not included in the output.
The include them, set *keep_separator* to ``True``.
>>> list(split_at('abcdcba', lambda x: x == 'b', keep_separator=True))
[['a'], ['b'], ['c', 'd', 'c'], ['b'], ['a']]
def setuptools._vendor.more_itertools.more.split_before |
( |
|
iterable, |
|
|
|
pred, |
|
|
|
maxsplit = -1 |
|
) |
| |
Yield lists of items from *iterable*, where each list ends just before
an item for which callable *pred* returns ``True``:
>>> list(split_before('OneTwo', lambda s: s.isupper()))
[['O', 'n', 'e'], ['T', 'w', 'o']]
>>> list(split_before(range(10), lambda n: n % 3 == 0))
[[0, 1, 2], [3, 4, 5], [6, 7, 8], [9]]
At most *maxsplit* splits are done. If *maxsplit* is not specified or -1,
then there is no limit on the number of splits:
>>> list(split_before(range(10), lambda n: n % 3 == 0, maxsplit=2))
[[0, 1, 2], [3, 4, 5], [6, 7, 8, 9]]
def setuptools._vendor.more_itertools.more.split_into |
( |
|
iterable, |
|
|
|
sizes |
|
) |
| |
Yield a list of sequential items from *iterable* of length 'n' for each
integer 'n' in *sizes*.
>>> list(split_into([1,2,3,4,5,6], [1,2,3]))
[[1], [2, 3], [4, 5, 6]]
If the sum of *sizes* is smaller than the length of *iterable*, then the
remaining items of *iterable* will not be returned.
>>> list(split_into([1,2,3,4,5,6], [2,3]))
[[1, 2], [3, 4, 5]]
If the sum of *sizes* is larger than the length of *iterable*, fewer items
will be returned in the iteration that overruns *iterable* and further
lists will be empty:
>>> list(split_into([1,2,3,4], [1,2,3,4]))
[[1], [2, 3], [4], []]
When a ``None`` object is encountered in *sizes*, the returned list will
contain items up to the end of *iterable* the same way that itertools.slice
does:
>>> list(split_into([1,2,3,4,5,6,7,8,9,0], [2,3,None]))
[[1, 2], [3, 4, 5], [6, 7, 8, 9, 0]]
:func:`split_into` can be useful for grouping a series of items where the
sizes of the groups are not uniform. An example would be where in a row
from a table, multiple columns represent elements of the same feature
(e.g. a point represented by x,y,z) but, the format is not the same for
all columns.
def setuptools._vendor.more_itertools.more.split_when |
( |
|
iterable, |
|
|
|
pred, |
|
|
|
maxsplit = -1 |
|
) |
| |
Split *iterable* into pieces based on the output of *pred*.
*pred* should be a function that takes successive pairs of items and
returns ``True`` if the iterable should be split in between them.
For example, to find runs of increasing numbers, split the iterable when
element ``i`` is larger than element ``i + 1``:
>>> list(split_when([1, 2, 3, 3, 2, 5, 2, 4, 2], lambda x, y: x > y))
[[1, 2, 3, 3], [2, 5], [2, 4], [2]]
At most *maxsplit* splits are done. If *maxsplit* is not specified or -1,
then there is no limit on the number of splits:
>>> list(split_when([1, 2, 3, 3, 2, 5, 2, 4, 2],
... lambda x, y: x > y, maxsplit=2))
[[1, 2, 3, 3], [2, 5], [2, 4, 2]]
def setuptools._vendor.more_itertools.more.spy |
( |
|
iterable, |
|
|
|
n = 1 |
|
) |
| |
Return a 2-tuple with a list containing the first *n* elements of
*iterable*, and an iterator with the same items as *iterable*.
This allows you to "look ahead" at the items in the iterable without
advancing it.
There is one item in the list by default:
>>> iterable = 'abcdefg'
>>> head, iterable = spy(iterable)
>>> head
['a']
>>> list(iterable)
['a', 'b', 'c', 'd', 'e', 'f', 'g']
You may use unpacking to retrieve items instead of lists:
>>> (head,), iterable = spy('abcdefg')
>>> head
'a'
>>> (first, second), iterable = spy('abcdefg', 2)
>>> first
'a'
>>> second
'b'
The number of items requested can be larger than the number of items in
the iterable:
>>> iterable = [1, 2, 3, 4, 5]
>>> head, iterable = spy(iterable, 10)
>>> head
[1, 2, 3, 4, 5]
>>> list(iterable)
[1, 2, 3, 4, 5]
def setuptools._vendor.more_itertools.more.stagger |
( |
|
iterable, |
|
|
|
offsets = (-1, 0, 1) , |
|
|
|
longest = False , |
|
|
|
fillvalue = None |
|
) |
| |
Yield tuples whose elements are offset from *iterable*.
The amount by which the `i`-th item in each tuple is offset is given by
the `i`-th item in *offsets*.
>>> list(stagger([0, 1, 2, 3]))
[(None, 0, 1), (0, 1, 2), (1, 2, 3)]
>>> list(stagger(range(8), offsets=(0, 2, 4)))
[(0, 2, 4), (1, 3, 5), (2, 4, 6), (3, 5, 7)]
By default, the sequence will end when the final element of a tuple is the
last item in the iterable. To continue until the first element of a tuple
is the last item in the iterable, set *longest* to ``True``::
>>> list(stagger([0, 1, 2, 3], longest=True))
[(None, 0, 1), (0, 1, 2), (1, 2, 3), (2, 3, None), (3, None, None)]
By default, ``None`` will be used to replace offsets beyond the end of the
sequence. Specify *fillvalue* to use some other value.
def setuptools._vendor.more_itertools.more.substrings |
( |
|
iterable | ) |
|
Yield all of the substrings of *iterable*.
>>> [''.join(s) for s in substrings('more')]
['m', 'o', 'r', 'e', 'mo', 'or', 're', 'mor', 'ore', 'more']
Note that non-string iterables can also be subdivided.
>>> list(substrings([0, 1, 2]))
[(0,), (1,), (2,), (0, 1), (1, 2), (0, 1, 2)]
def setuptools._vendor.more_itertools.more.substrings_indexes |
( |
|
seq, |
|
|
|
reverse = False |
|
) |
| |
Yield all substrings and their positions in *seq*
The items yielded will be a tuple of the form ``(substr, i, j)``, where
``substr == seq[i:j]``.
This function only works for iterables that support slicing, such as
``str`` objects.
>>> for item in substrings_indexes('more'):
... print(item)
('m', 0, 1)
('o', 1, 2)
('r', 2, 3)
('e', 3, 4)
('mo', 0, 2)
('or', 1, 3)
('re', 2, 4)
('mor', 0, 3)
('ore', 1, 4)
('more', 0, 4)
Set *reverse* to ``True`` to yield the same items in the opposite order.
def setuptools._vendor.more_itertools.more.unique_to_each |
( |
* |
iterables | ) |
|
Return the elements from each of the input iterables that aren't in the
other input iterables.
For example, suppose you have a set of packages, each with a set of
dependencies::
{'pkg_1': {'A', 'B'}, 'pkg_2': {'B', 'C'}, 'pkg_3': {'B', 'D'}}
If you remove one package, which dependencies can also be removed?
If ``pkg_1`` is removed, then ``A`` is no longer necessary - it is not
associated with ``pkg_2`` or ``pkg_3``. Similarly, ``C`` is only needed for
``pkg_2``, and ``D`` is only needed for ``pkg_3``::
>>> unique_to_each({'A', 'B'}, {'B', 'C'}, {'B', 'D'})
[['A'], ['C'], ['D']]
If there are duplicates in one input iterable that aren't in the others
they will be duplicated in the output. Input order is preserved::
>>> unique_to_each("mississippi", "missouri")
[['p', 'p'], ['o', 'u', 'r']]
It is assumed that the elements of each iterable are hashable.
def setuptools._vendor.more_itertools.more.windowed |
( |
|
seq, |
|
|
|
n, |
|
|
|
fillvalue = None , |
|
|
|
step = 1 |
|
) |
| |
Return a sliding window of width *n* over the given iterable.
>>> all_windows = windowed([1, 2, 3, 4, 5], 3)
>>> list(all_windows)
[(1, 2, 3), (2, 3, 4), (3, 4, 5)]
When the window is larger than the iterable, *fillvalue* is used in place
of missing values:
>>> list(windowed([1, 2, 3], 4))
[(1, 2, 3, None)]
Each window will advance in increments of *step*:
>>> list(windowed([1, 2, 3, 4, 5, 6], 3, fillvalue='!', step=2))
[(1, 2, 3), (3, 4, 5), (5, 6, '!')]
To slide into the iterable's items, use :func:`chain` to add filler items
to the left:
>>> iterable = [1, 2, 3, 4]
>>> n = 3
>>> padding = [None] * (n - 1)
>>> list(windowed(chain(padding, iterable), 3))
[(None, None, 1), (None, 1, 2), (1, 2, 3), (2, 3, 4)]
def setuptools._vendor.more_itertools.more.windowed_complete |
( |
|
iterable, |
|
|
|
n |
|
) |
| |
Yield ``(beginning, middle, end)`` tuples, where:
* Each ``middle`` has *n* items from *iterable*
* Each ``beginning`` has the items before the ones in ``middle``
* Each ``end`` has the items after the ones in ``middle``
>>> iterable = range(7)
>>> n = 3
>>> for beginning, middle, end in windowed_complete(iterable, n):
... print(beginning, middle, end)
() (0, 1, 2) (3, 4, 5, 6)
(0,) (1, 2, 3) (4, 5, 6)
(0, 1) (2, 3, 4) (5, 6)
(0, 1, 2) (3, 4, 5) (6,)
(0, 1, 2, 3) (4, 5, 6) ()
Note that *n* must be at least 0 and most equal to the length of
*iterable*.
This function will exhaust the iterable and may require significant
storage.
def setuptools._vendor.more_itertools.more.zip_offset |
( |
* |
iterables, |
|
|
|
offsets, |
|
|
|
longest = False , |
|
|
|
fillvalue = None |
|
) |
| |
``zip`` the input *iterables* together, but offset the `i`-th iterable
by the `i`-th item in *offsets*.
>>> list(zip_offset('0123', 'abcdef', offsets=(0, 1)))
[('0', 'b'), ('1', 'c'), ('2', 'd'), ('3', 'e')]
This can be used as a lightweight alternative to SciPy or pandas to analyze
data sets in which some series have a lead or lag relationship.
By default, the sequence will end when the shortest iterable is exhausted.
To continue until the longest iterable is exhausted, set *longest* to
``True``.
>>> list(zip_offset('0123', 'abcdef', offsets=(0, 1), longest=True))
[('0', 'b'), ('1', 'c'), ('2', 'd'), ('3', 'e'), (None, 'f')]
By default, ``None`` will be used to replace offsets beyond the end of the
sequence. Specify *fillvalue* to use some other value.